Range Problems Using Conditional Testing

Problem: Range Test 1

Write a JAVA program named isInRange1 that prompts the user to enter two integers, the first to identify the lowest value of a range of integers, the second to identify the upper value of a given range of integers.

The program will then prompt the user to enter an integer that is to be tested to see if it falls within the range of the low value and high value, inclusive.

For the purposes of this program you may assume that the user will input the low value first, and the high value second, therefore no data validation is required.

As output, the program will display a message “value is in range” if the search value is between or equal to one of the range values. Otherwise, the program will display a message “value is not in range”.

Sample Program Data

Program Run	First Input Value	Second Input Value	Test Value	Output Message
1	3	12	7	7 is in range
2	9	3	6	6 is not in range

Initial Questions

Algorithm


Define a class named IsInRange1
Provide method main

//Variable Declarations
int low, high, testValue;  //store user input
Scanner kbd;  //provide input from keyboard

//User Prompt
Prompt user to enter three integers, a low value, a high value and a value to be tested
Store user input in variables low, high, testValue

//Program logic
IF testValue >= low && testValue <= high
    Display message “The value testValue is in range”
ELSE
    Display message “The value testValue is not in range”

//End Program

Solution


 1 import java.util.Scanner;
 2 
 3 public class IsInRange
 4 {
 5    public static void main(String [] args)
 6    {
 7       int low;
 8       int high;
 9       int testValue;
10       
11       Scanner kbd = new Scanner(System.in);
12       
13       System.out.println("Please enter the low value: ");
14       low = kbd.nextInt();
15       System.out.println("Please enter the high value: ");
16       high = kbd.nextInt();
17       
18       System.out.println("Please enter the value to be tested: ");
19       testValue = kbd.nextInt();
20       
21       if(testValue >= low && testValue <= high)
22          System.out.println("The value " + testValue +
23                               " is in range.");
24                               
25       else
26          System.out.println("The value " + testValue +
27                               " is not in range.");
28    }
29 }
30 /*OUTPUT
31 //Test 1
32 Please enter the low value: 
33 3
34 Please enter the high value: 
35 12
36 Please enter the value to be tested: 
37 7
38 The value 7 is in range.
39 
40 //Test 2
41 Please enter the low value: 
42 9
43 Please enter the high value: 
44 3
45 Please enter the value to be tested: 
46 6
47 The value 6 is not in range.
48 */

Video

Problem: Range Test 2

Write a JAVA program named isInRange2 that prompts the user to enter two integers that represent the outer bounds of a range of values.

The program will then prompt the user to enter an integer that is to be tested to see if it falls within the range of the first two integers, inclusive.

Note: for purposes of this program, the user is not obligated to enter the lowest value first.

Sample Program Data

Program Run	First Input Value	Second Input Value	Test Value	Output Message
1	3	12	7	7 is in range
2	12	3	6	6 is in range
3	6	12	3	3 is not in range

Initial Questions

Algorithm


Define a class named IsInRange2
Provide method main

//Variable Declarations
int rangeVal1, rangeVal2, testValue;  //store user input
Scanner kbd;  //provide input from keyboard

//User Prompt
Prompt user to enter three integers, two range values and a value to be tested
Store user input in variables rangeVal1, rangeVal2, testValue

//Program logic
IF testValue >= rangeVal1 && testValue <= rangeVal2
OR testValue >= rangeVal2 && testValue <= rangeVal1
    Display message “The value testValue is in range”
ELSE
    Display message “The value testValue is not in range”

//End Program

Solution


 1 import java.util.Scanner;
 2 
 3 public class IsInRange2
 4 {
 5    public static void main(String [] args)
 6    {
 7       int rangeVal1;
 8       int rangeVal2;
 9       int testValue;
10       
11       Scanner kbd = new Scanner(System.in);
12       
13       System.out.println("Please enter the first value: ");
14       rangeVal1 = kbd.nextInt();
15       System.out.println("Please enter the second value: ");
16       rangeVal2 = kbd.nextInt();
17       
18       System.out.println("Please enter the value to be tested: ");
19       testValue = kbd.nextInt();
20       
21       //create range parameters from rangeVal1 to rangeVal2
22       if(testValue >= rangeVal1 && testValue <= rangeVal2 ||
23             testValue >= rangeVal2 && testValue <= rangeVal1)
24       {      
25          System.out.println("The value " + testValue +
26                               " is in range.");
27       }                       
28       else
29       {
30          System.out.println("The value " + testValue +
31                               " is not in range.");
32       }
33    }
34 }
35 /*OUTPUT
36 //Test 1
37 Please enter the first value: 
38 3
39 Please enter the second value: 
40 12
41 Please enter the value to be tested: 
42 7
43 The value 7 is in range.
44 
45 //Test 2
46 Please enter the first value: 
47 12
48 Please enter the second value: 
49 3
50 Please enter the value to be tested: 
51 6
52 The value 6 is in range.
53 
54 //Test 3
55 Please enter the first value: 
56 6
57 Please enter the second value: 
58 12
59 Please enter the value to be tested: 
60 3
61 The value 3 is not in range.
62 */

Video

Problem: Find Minimum Value

Write a JAVA program named MinVal that prompts the user to input 3 integer values. As output the program will display the smallest of the three.

Sample input/output

Input values: 7 9 2
Output: 2

Initial Questions

Algorithm


Define a class named MinVal
Provide method main(  )

//Variable Declarations
int a, b, c;    //store user input
int smallest;   //store the smallest value found during comparisons
Scanner kbd;    //provide input from keyboard

//User Prompt
Prompt user to enter three integers
Store user input in a, b, c

//Program logic
IF a <= b AND a <= c
    Assign a to smallest
ElSE IF b <= a AND b <= c
    Assign b to smallest
ELSE
    Assign c to smallest

//Program output
    Display message “The smallest of a-value, b-value and c-value is: smallest-value”

//End Program

Solution


/*
Write a JAVA program named MinVal that prompts the user to input 3 integer values. 
As output the program will display the smallest of the three.

For example, if the following three numbers were to be entered: 	7     9     2
the output would be the following:					2
*/

import java.util.Scanner;

public class MinVal
{
   public static void main(String [] args)
   {
      //variable declarations
      int a = 0, b = 0, c = 0;   //store user input
      int smallest = 0;          //store the smallest of three
      Scanner kbd = new Scanner(System.in);
      
      //user prompt
      System.out.println("Please enter the first of three integers: ");
      a = kbd.nextInt();
      System.out.println("Please enter the second of three integers: ");
      b = kbd.nextInt();
      System.out.println("Please enter the third of three integers: ");
      c = kbd.nextInt();
      
      //program logic
      if(a <= b && a <= c)       //see if a is the smallest
         smallest = a;
      else if(b <= a && b <= c)  //see if b is the smallest
         smallest = b;
      else                       //if neither a nor b are smallest
         smallest = c;           //c must be the smallest
         
      //program output
      System.out.println("\nThe smallest of " + a + ", " + b + 
                         " and " + c + " is: " + smallest);
   }
}

Video

Problem: Find the Maximum Value

Write a JAVA program named MaxVal that prompts the user to input 3 integer values. As output the program will display the largest of the three.

Input values: 7 9 2
Output: 9

Initial Questions

Algorithm



Define a class named MaxVal
Provide method main(  )

//Variable Declarations
int a, b, c;    //store user input
int largest;   //store the largest value found during comparisons
Scanner kbd;    //provide input from keyboard

//User Prompt
Prompt user to enter three integers
Store user input in a, b, c

//Program logic
IF a >= b AND a >= c
    Assign a to largest
ElSE IF b >= a AND b >= c
    Assign b to largest
ELSE
    Assign c to largest

//Program output
    Display message “The largest of a-value, b-value and c-value is: largest-value”

//End Program

Solution


 /*
Write a JAVA program named MaxVal that prompts the user to input 3 integer values. 
As output the program will display the largest of the three.

For example, if the following three numbers were to be entered: 	7     9     2
the output would be the following:					9
*/
import java.util.Scanner;

public class MaxVal
{
   public static void main(String [] args)
   {
      //variable declarations
      int a = 0, b = 0, c = 0;   //store user input
      int largest = 0;          //store the largest of three
      Scanner kbd = new Scanner(System.in);
      
      //user prompt
      System.out.println("Please enter the first of three integers: ");
      a = kbd.nextInt();
      System.out.println("Please enter the second of three integers: ");
      b = kbd.nextInt();
      System.out.println("Please enter the third of three integers: ");
      c = kbd.nextInt();
      
      //program logic
      if(a >= b && a >= c)       //see if a is the largest
         largest = a;
      else if(b >= a && b >= c)  //see if b is the largest
         largest = b;
      else                       //if neither a nor b are largest
         largest = c;           //c must be the largest
         
      //program output
      System.out.println("\nThe largest of " + a + ", " + b + 
                         " and " + c + " is: " + largest);
   }
}

Video

Range Problems Using Conditional Testing

Problem: Range Test 1

Sample Program Data

Not Yet Available

Problem: Range Test 2

Sample Program Data

Not Yet Available

Problem: Find Minimum Value

Not Yet Available

Problem: Find the Maximum Value

Not Yet Available